By Behrouz A. Forouzan, Richard F. Gilberg
This moment variation expands upon the cast, sensible origin verified within the first version of the textual content. a brand new four-part organizational constitution raises the pliability of the textual content, and all fabric is gifted in an easy demeanour followed via an array of examples and visible diagrams.
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Extra info for Data Structures: A Pseudocode Approach with C (2nd Edition)
9 Practice Sets 5. Identify the composite data types for your primary programming language. 6. Reorder the following efficiencies from smallest to largest: a. b. c. d. e. 2n n! n5 10,000 nlog(n) 7. Reorder the following efficiencies from smallest to largest: a. b. c. d. 5 8. Determine the big-O notation for the following: a. b. c. d. 5n5/2 + n2/5 6log(n) + 9n 3n4 + nlog(n) 5n2+ n3/2 9. Calculate the run-time efficiency of the following program segment: for (i = 1; i <= n; i++) printf("%d ", i); 10.
It contains three variables: an integer, a floating-point number, and a void pointer. At different times in the program the pointer can be set to the address of the integer value or of the floating-point value. Figure 1-7 shows the situation. void* p; int i; float f; p = &i; ... p = &f; p = &i p = &f p p i p f FIGURE 1-7 Pointers for Program 1-1 Program 1-1 uses a pointer to void that we can use to print either an integer or a floating-point number. Chapter 1 Basic Concepts 19 PROGRAM 1-1 Demonstrate Pointer to void 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 /* Demonstrate pointer to void.
12. ) 13. ) 14. Given that the efficiency of an algorithm is 5n2, if a step in this algorithm takes 1 nanosecond (10–9 seconds), how long does it take the algorithm to process an input of size 1000? Chapter 1 Basic Concepts 41 15. Given that the efficiency of an algorithm is n3, if a step in this algorithm takes 1 nanosecond (10–9 seconds), how long does it take the algorithm to process an input of size 1000? 16. Given that the efficiency of an algorithm is 5nlog(n), if a step in this algorithm takes 1 nanosecond (10– 9 seconds), how long does it take the algorithm to process an input of size 1000?