By Dr Antonio Gulli
This e-book offers a set of Dynamic programming difficulties, their answer, and the C++ code concerning them.
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Additional info for A Collection of Dynamic Programming Interview Questions Solved in C++
Substr(longestStart, maxLen); } Complexity Complexity is and space is. Providing a solution with reduced space is left as exercise. 14. String Palindromes -– Given a string, find the minimum number of characters to be inserted for converting the string into a palindrome Solution Consider the string and define as the number of characters to be inserted for getting a palindrome. We have: The base case are if and A dynamic programming implementation can be realized by adopting a which stores the minimum number of insertions needed to convert into a palindrome.
LBS – Given an array of integers, find the longest bitonic sequence 20. Box Stacking – Given a set of boxes, compute the largest stack of boxes. A box can be stacked only on top of another box with larger base. 21. Sum Subset -– Given an array of integers of size, partition it in such a way that the two subsets have equal sum 22. Partition Set – partition a multiset S of positive integers into two subsets and, such that the sum of the numbers in equals the sum of the numbers in 23. Segment Partition -– Given a segment of integer length, cut it into different integer parts in such a way to maximize the product of the lengths of all parts.
B) Bottom-up approach: This requires a reformulation of the recursive mathematical definition where subproblems are solved first and their solutions used to build-on and achieve solutions for bigger subproblems In this book we will review a collection of Dynamic programming problems, their solution, and the C++ code related to them. Many of those problems are commonly asked during interviews and can be frequently found on Internet web sites devoted to interviews’ preparation. 1. Fibonacci numbers Solution The first two numbers in the Fibonacci sequence are 0 and 1, and each subsequent number is the sum of the previous two.